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JEE Mains · Physics · STD 11 - Oscillations
  • JEE Mains 2021
  • Medium
  • MCQ

In a simple harmonic oscillation, what fraction of total mechanical energy is in the form of kinetic energy, when the particle is midway between mean and extreme position.

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Answer & Solution

Correct Answer

(C) \(\frac{3}{4}\)

Step-by-step Solution

Detailed explanation

\(K =\frac{1}{2} m \omega^{2}\left( A ^{2}- x ^{2}\right)\)

\(=\frac{1}{2} m \omega^{2}\left( A ^{2}-\frac{ A ^{2}}{4}\right)\)

\(=\frac{1}{2} m \omega^{2}\left(\frac{3 A ^{2}}{4}\right)\)

\(K =\frac{3}{4}\left(\frac{1}{2} m \omega^{2} A ^{2}\right)\)

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