JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2023
- Easy
- Numerical
The moment of inertia of semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is \(\frac{1}{ x } MR ^2\), where \(R\) is the radius and \(M\) is the mass of semicircular ring. The value of \(x\) will be \(...........\)
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Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
The moment of inertia of semicircular ring about axis passing through centre of ring and perpendicular to plane of ring is \(= MR ^2\) so \(x=1\)
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