JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
If an emitter current is changed by \(4\, mA ,\) the collector current changes by \(3.5\, mA\). The value of \(\beta\) will be
- A \(7\)
- B \(0.5\)
- C \(0.875\)
- D \(3.5\)
Answer & Solution
Correct Answer
(A) \(7\)
Step-by-step Solution
Detailed explanation
\(I _{\varepsilon}= I _{ C }+ I _{ B }\) \(\Rightarrow \Delta I _{\varepsilon}=\Delta I _{ C }+\Delta I _{ B }\) \(4 mA =3.5 mA +\Delta I _{ B }\) \(\Rightarrow \Delta I _{ B }=0.5 mA\) \(\Rightarrow \beta=\frac{\Delta I _{ C }}{\Delta I _{ B }}\) \(\beta=\frac{3.5}{0.5}\)…
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