JEE Mains · Physics · STD 11 - 3.2 motion in plane
For particle \(P\) revolving round the centre \(O\) with radius of circular path \(r\) and angular velocity \(\omega\), as shown in below figure, the projection of \(OP\) on the \(x\)-axis at time \(t\) is \(.................\).
- A \(x(t)=r \cos \left(\omega t+\frac{\pi}{6}\right)\)
- B \(x(t)=r \cos (\omega t)\)
- C \(x(t)=r \sin \left(\omega t+\frac{\pi}{6}\right)\)
- D \(x(t)=r \cos \left(\omega t-\frac{\pi}{6} \omega\right)\)
Answer & Solution
Correct Answer
(A) \(x(t)=r \cos \left(\omega t+\frac{\pi}{6}\right)\)
Step-by-step Solution
Detailed explanation
\(x ( t )=r \cos \left(\omega t +30^{\circ}\right)\) \(x ( t )=r \cos (\omega t +\pi / 6)\)
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