JEE Mains · Physics · STD 11 - Motion in plane
- JEE Mains 2023
- Easy
- MCQ
For particle \(P\) revolving round the centre \(O\) with radius of circular path \(r\) and angular velocity \(\omega\), as shown in below figure, the projection of \(OP\) on the \(x\)-axis at time \(t\) is \(.................\).

Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(x(t)=r \cos \left(\omega t+\frac{\pi}{6}\right)\)
Step-by-step Solution
Detailed explanation
\(x ( t )=r \cos \left(\omega t +30^{\circ}\right)\)
\(x ( t )=r \cos (\omega t +\pi / 6)\)
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