JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
\( X_{2}(g) + Y_{2}(g) \rightleftharpoons 2Z(g) \),
\(X _2(g)\) and \(Y _2(g)\) are added to a 1 L flask and it is found that the system attains the above equilibrium at \(T ( K )\) with the number of moles of \(X _2(g), Y _2(g)\) and \(Z ( g )\) being 3,3 and 9 mol respectively (equilibrium moles). Under this conditions of equilibrium, 10 mol of \(Z ( g )\) is added to the flask and the temperature is maintained at \(T ( K )\). Then the number of moles of \(Z ( g )\) in the flask when the new equilibrium is established is _________ . (Nearest integer).
- A 12
- B 15
- C 18
- D 20
Answer & Solution
Correct Answer
(B) 15
Step-by-step Solution
Detailed explanation
\(X _2(g)+ Y _2(g) \rightleftharpoons 2 Z ( g )\) \(K_C=\frac{(9)^2}{3 \times 3}=9\) Now 10 moles of \(Z\) are added then reaction will move in backward direction. \(X _2(g)+ Y _2(g) \rightleftharpoons 2 Z ( g )\) \(3+X \quad 3+X \quad 19-2 X\)…
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