JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2026
- Medium
- MCQ
Distance between an object and three times magnified real image is 40 cm . The focal length of the mirror used is _________ cm .
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(-15\)
Step-by-step Solution
Detailed explanation
\(m=-3=\frac{v}{u}\)
\(v=-3u\)
\(|v|-|u|=40\)
\(u=20~cm,\)
\(v=60~cm\)
\(\therefore \frac{1}{v}+\frac{1}{u}=\frac{1}{f}\)
\(\frac{1}{-60}+\frac{1}{-20}=\frac{1}{ f }\)
\(f =-15 cm\)
\(v=-3u\)
\(|v|-|u|=40\)
\(u=20~cm,\)
\(v=60~cm\)
\(\therefore \frac{1}{v}+\frac{1}{u}=\frac{1}{f}\)
\(\frac{1}{-60}+\frac{1}{-20}=\frac{1}{ f }\)
\(f =-15 cm\)
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