JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
In Carius method for estimation of halogens, \(0.2\, \mathrm{~g}\) of an organic compound gave \(0.188 \,\mathrm{~g}\) of \(\mathrm{AgBr}\). The percentage of bromine in the compound is ...... . (Nearest integer) [Atomic mass: \(\mathrm{Ag}=108, \mathrm{Br}=80\) ]
- A \(4\)
- B \(400\)
- C \(40\)
- D \(0.40\)
Answer & Solution
Correct Answer
(C) \(40\)
Step-by-step Solution
Detailed explanation
\(\mathrm{n}_{\mathrm{AgBr}}=\frac{0.188 \mathrm{~g}}{188 \mathrm{~g} / \mathrm{mol}}=10^{-3}\, \mathrm{~mol}\) \(\Rightarrow \mathrm{n}_{\mathrm{Br}}=\mathrm{n}_{\lambda_{\mathrm{kBt}}}=0.001\, \mathrm{~mol}\)…
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