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JEE Mains · Physics · STD 12 - 1. Electric charges and fields

A charge of \(4\,\mu C\) is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be.

  1. A \(1\; \mu C\) and \(3\; \mu C\)
  2. B \(2\; \mu C\) and \(2\; \mu C\)
  3. C \(0\) and \(4\; \mu C\)
  4. D \(1.5\; \mu C\) and \(2.5\; \mu C\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\; \mu C\) and \(2\; \mu C\)

Step-by-step Solution

Detailed explanation

\(F =\frac{ Kq (4- q )}{ d ^{2}}\) \(\frac{ dF }{ dq }=\frac{ K }{ d ^{2}}[4-2 q ]=0\) \(q =2\)
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