JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
\(37.8 \mathrm{~g} \mathrm{~N}_2 \mathrm{O}_5\) was taken in a 1 L reaction vessel and allowed to undergo the following reaction at 500 K
\(2 \mathrm{~N}_2 \mathrm{O}_{5(\mathrm{~g})} \rightleftharpoons 2 \mathrm{~N}_2 \mathrm{O}_{4(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}\)
The total pressure at equilibrium was found to be 18.65 bar.
Then, \(\mathrm{Kp}=\) ______ \(\times 10^{-2}\) [nearest integer]
Assume \(\mathrm{N}_2 \mathrm{O}_5\) to behave ideally under these conditions.
Given: \(\mathrm{R}=0.082\) bar \(\mathrm{L} \mathrm{mol}^{-1} \mathrm{~K}^{-1}\)
- A 900
- B 950
- C 962
- D 942
Answer & Solution
Correct Answer
(C) 962
Step-by-step Solution
Detailed explanation
Initial pressure of \(\mathrm{N}_2 \mathrm{O}_5\) \(\begin{aligned} & =\frac{\frac{37.8}{108} \times 0.082 \times 500}{1}=14.35 \text { bar } \\ & 2 \mathrm{~N}_2 \mathrm{O}_5 \rightleftharpoons 2 \mathrm{~N}_2 \mathrm{O}_4+\mathrm{O}_2 \end{aligned}\)…
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