JEE Mains · Physics · STD 11 - 11. thermodynamics
\(300 \,cal\). of heat is given to a heat engine and it rejects \(225 \,cal\). of heat. If source temperature is \(227^{\circ} C\), then the temperature of sink will be____\({ }^{\circ} C\).
- A \(107\)
- B \(99\)
- C \(100\)
- D \(102\)
Answer & Solution
Correct Answer
(D) \(102\)
Step-by-step Solution
Detailed explanation
\(1-\frac{Q_{2}}{Q_{1}}=1-\frac{T_{2}}{T_{1}}\) \(\frac{ Q _{2}}{ Q _{1}}=\frac{ T _{2}}{ T _{1}}\) \(\frac{225}{300}=\frac{ T _{2}}{500}\) \(\frac{500 \times 225}{300}= T _{2}\) \(375= T _{2}\) \(102^{\circ} C = T _{2}\)
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