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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2022
  • Medium
  • Numerical

\(300 \,cal\). of heat is given to a heat engine and it rejects \(225 \,cal\). of heat. If source temperature is \(227^{\circ} C\), then the temperature of sink will be____\({ }^{\circ} C\).

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Answer & Solution

Correct Answer

(D) \(102\)

Step-by-step Solution

Detailed explanation

\(1-\frac{Q_{2}}{Q_{1}}=1-\frac{T_{2}}{T_{1}}\)

\(\frac{ Q _{2}}{ Q _{1}}=\frac{ T _{2}}{ T _{1}}\)

\(\frac{225}{300}=\frac{ T _{2}}{500}\)

\(\frac{500 \times 225}{300}= T _{2}\)

\(375= T _{2}\)

\(102^{\circ} C = T _{2}\)

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