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JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)

Use the following data :
Substance\(\frac{\Delta_{ f } H ^{\ominus}(500 K)}{ kJ mol ^{-1}}\)\(\frac{ S ^{\ominus}(500 K)}{ JK ^{-1} mol^{-1}}\)
\(AB ( g )\)32222
\(A _2(g)\)6146
\(B _2(g)\)X280

One mole each of \(A _2(g)\) and \(B _2(g)\) are taken in a 1L closed flask and allowed to establish the equilibrium at 500 K .
\(A _2(g)+ B _2(g) \rightleftharpoons 2 AB ( g )\)
The value of in \(x\left( kJ mol ^{-1}\right)\) is ............ (Nearest integer)
(Given: \(\log K =2.2 R =8.3 JK ^{-1} mol^{-1}\) )

  1. A 60
  2. B 70
  3. C 80
  4. D 90
Verified Solution

Answer & Solution

Correct Answer

(B) 70

Step-by-step Solution

Detailed explanation

\(A _2+ B _2 \xrightarrow{500 K} 2 AB \log K =2.2\) \(\Delta H ^{\circ}=(2 \times 32)-(6+ x )=(58- x ) kJ\) \(\Delta S ^{\circ}=(2 \times 222)-(146+280)=18\) Joule \(\Delta G ^{\circ}=- RT \ln K\) \(\Delta G ^{\circ}=-\frac{8.314 \times 500 \times 2.2 \times 2.303}{1000}\)…
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