JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
One mole each of He and \(A(g)\) are taken in a \(10\) L closed flask and heated to \(400\) K to establish the following equilibrium. \(A(g) \rightleftharpoons B(g)\). \(K_c\) for this reaction at \(400\) K is \(4.0\). The partial pressures (in atm) of He and \(B(g)\) are respectively (at equilibrium) (Assume He, \(A(g)\) and \(B(g)\) behave as ideal gases) (Given: \(R = 0.082\) L atm K\(^{-1}\) mol\(^{-1}\))
- A \(3.28, 2.624\)
- B \(2.624, 3.28\)
- C \(3.28, 0.656\)
- D \(0.656, 6.56\)
Answer & Solution
Correct Answer
(A) \(3.28, 2.624\)
Step-by-step Solution
Detailed explanation
The given reaction is \(A(g) \rightleftharpoons B(g)\). Let the initial moles of \(A\) be \(1\) and at equilibrium, let \(x\) moles of \(A\) dissociate. Moles at equilibrium: \(n_A = 1 - x\) \(n_B = x\) Since \(\Delta n_g = 0\), the equilibrium constant \(K_c\) can be written in…
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