JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
The reaction of ozone with oxygen atoms in the presence of chlorine atoms can occur by a two step process shown below \({O_3}(g)\, + \,C{l^ * }(g)\, \to \,{O_2}(g) + Cl{O^ * }(g)\) ..... \((i)\) \([{K_i} = 5.2 \times {10^9}\,\,L\,mo{l^{ - 1}}\,{s^{ - 1}}]\) \(Cl{O^ * }(g) + {O^ * }(g)\, \to \,{O_2}(g) + \,C{l^ * }(g)\) ..... \((ii)\) \([{K_{ii}} = 2.6 \times {10^{10}}\,\,L\,mo{l^{ - 1}}\,{s^{ - 1}}]\) The closest rate constant for the overall reaction \({O_3}(g){\mkern 1mu} + {\mkern 1mu} {O^*}(g){\mkern 1mu} \to {\mkern 1mu} 2{O_2}(g)\) is ........... \(L\,\,mo{l^{ - 1}}\,{s^{ - 1}}\)
- A \(1.4 \times {10^{20}}\)
- B \(3.1 \times {10^{10}}\)
- C \(5.2 \times {10^9}\)
- D \(2.6 \times {10^{10}}\)
Answer & Solution
Correct Answer
(A) \(1.4 \times {10^{20}}\)
Step-by-step Solution
Detailed explanation
On adding eq. \((i)\) and eq. \((ii)\) we get \({{O}_{3}}(g)+O(g)\to 2{{O}_{2}}(g)\) Hence overall rate constant \(=\,K_i\times K_{ii}\) \( = \,5.2 \times \,{10^9}\, \times \,2.6\, \times \,{10^{10}}\, \approx \,\) \(1.4\, \times \,{10^{20}}\,mo{l^{ - 1}}\,L{s^{ - 1}}\)…
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