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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2021
  • Medium
  • Numerical

A current through a wire depends on time as \(i =\alpha_{0} t +\beta t ^{2}\) where \(\alpha_{0}=20 A / s\) and \(\beta=8 As ^{-2} .\) Find the charge crossed through a section of the wire in \(15 \,s\) (in \(C\))

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Answer & Solution

Correct Answer

(B) \(11250\)

Step-by-step Solution

Detailed explanation

\(i =20 t +8 t ^{2}\)

\(i =\frac{ dq }{ dt } \Rightarrow \int d q =\int idt\)

\(\Rightarrow q =\int_{0}^{15}\left(20 t +8 t ^{2}\right) dt\)

\(q =\left(\frac{20 t ^{2}}{2}+\frac{8 t ^{3}}{3}\right)_{0}^{15}\)

\(q =10 \times(15)^{2}+\frac{8(15)^{3}}{3}\)

\(q =2250+9000\)

\(q =11250 C\)

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