JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Consider titration of \(NaOH\) solution versus \(1.25\, M\) oxalic acid solution. At the end point following burette readings were obtained. \((i)\) \(4.5\, mL\) \(\quad (ii)\) \(4.5\, mL\) \(\quad (iii)\) \(4.4\, mL\) \((iv)\) \(4.4\, mL\) \(\quad (v)\) \(4.4\, mL\) If the volume of oxalic acid taken was \(10.0 \,mL\) then the molarity of the \(NaOH\) solution is .... \(M.\) (Rounded-off to the nearest integer)
- A \(6\)
- B \(16\)
- C \(32\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(6\)
Step-by-step Solution
Detailed explanation
\(V _{ NaOH }=4.4\, ml\) eq. of \(NaOH =\) eq. of \(H _{2} C _{2} O _{4}\) or, \(M \times 4.4 \times 1=1.25 \times 10 \times 2\) or, \(M =5.68\, M\) \(\therefore\) Nearest integer answer is \(6.\)
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