JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
Molar conductivity of a weak acid HQ of concentration 0.18 M was found to be 1/30 of the molar conductivity of another weak acid HZ with concentration of 0.02 of M. If \(\lambda_{Q^{-}}^0\) a happened to be equal with, \(\lambda_{Z^{-}}^0\), then the difference of the \(pK _{ a }\) values of the two weak acids \(\left( pK _{ a }( HQ )- pK _{ a }( HZ )\right)\) is ________ (Nearest integer).
[Given: degree of dissociation (\(\alpha\)) << 1 for both weak acids, λº: limiting molar conductivity of ions]
- A 2
- B 1
- C 3
- D 4
Answer & Solution
Correct Answer
(A) 2
Step-by-step Solution
Detailed explanation
\(K _{ a }( HQ )= C _1 \alpha_1^2 \quad\alpha_1=\frac{\lambda_{ m }( HQ )}{\lambda_{ m }^{\infty}( HQ )}\) \(K _{ a }( HZ )= C _2 \alpha_2^2 \quad \alpha_2=\frac{\lambda_{ m }( HZ )}{\lambda_{ m }^{\infty}( HZ )}\)…
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