JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
The half-life of radioisotopic bromine \(- 82\) is \(36\) hours. The fraction which remains after one day is _______ \(\times 10^{-2}\). (Given antilog \(0.2006=1.587\) )
- A \(41\)
- B \(52\)
- C \(63\)
- D \(36\)
Answer & Solution
Correct Answer
(C) \(63\)
Step-by-step Solution
Detailed explanation
Half life of bromine \(-82=36\) hours \( \mathrm{t}_{1 / 2}=\frac{0.693}{\mathrm{~K}} \) \( \mathrm{~K}=\frac{0.693}{36}=0.01925 \mathrm{hr}^{-1} \) \(1^{\text {st }}\) order rxn kinetic equation \( t=\frac{2.303}{K} \log \frac{a}{a-x} \)…
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