JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
The rate law for the reaction below is given by the expression \(k\left[ A \right]\left[ B \right]\) \(A + B \to\) Product If the concentration of \(B\) is increased from \(0.1\) to \(0.3\, mole\), keeping the value of \(A\) at \(0.1\, mole\), the rate constant will be
- A \(3k\)
- B \(9k\)
- C \(k/3\)
- D \(k\)
Answer & Solution
Correct Answer
(D) \(k\)
Step-by-step Solution
Detailed explanation
Rate constant is independent of concentration
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