JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
A first order reaction has the rate constant, \(k =4.6\) \(\times 10^{-3} s ^{-1}\). The number of correct statement/s from the following is/are Given : \(\log 3=0.48\) \(A.\) Reaction completes in \(1000\,s\). \(B.\) The reaction has a half-life of \(500\, s\). \(C.\) The time required for \(10\, \%\) completion is 25 times the time required for \(90 \,\%\) completion. \(D.\) The degree of dissociation is equal to \(\left(1-e^{-k t}\right)\). \(E.\) The rate and the rate constant have the same unit.
- A \(4\)
- B \(6\)
- C \(8\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(t_{ LAS }=\frac{1}{ K } \ln \left(\frac{ a }{ a - x }\right)=\frac{1}{ K } \ln \left(\frac{100}{90}\right)\) \(t _{10 s }=\frac{2.303}{ K }(\log 10-\log 9)\) \(t _{10 s }=\frac{2.093}{ K } \times(0.04)\) Similarly, \(t _{90 \% 6}=\frac{1}{ K } \ln \left(\frac{100}{10}\right)\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- For conversion of compound \(A \rightarrow B\), the rate constant of the reaction was found to be \(4.6 \times 10^{-5}\,L\, mol ^{-1}\, s ^{-1}\). The order of the reaction is \(..........\)JEE Mains 2023 Medium
- Match List \(I\) with List \(II\) :
Choose the correct answer from the options given below :List \(I\) (Molecule Species) List \(II\) (Property Shape) \((A)\) \(\mathrm{SO}_2 \mathrm{Cl}_2\) \((I)\) Paramagnetic \((B)\) \(NO\) \((II)\) Diamagnetic \((C)\) \(\mathrm{NO}_2^{-}\) \((III)\) Tetrahedral \((D)\) \(\mathrm{I}_3^{-}\) \((IV)\) Linear JEE Mains 2024 Medium - Given below are two statements : Statement \(I\) : Gallium is used in the manufacturing of thermometers. Statement \(II\) : A thermometer containing gallium is useful for measuring the freezing point ( \(256 \mathrm{~K}\) ) of brine solution. In the light of the above statement, choose the correct answer from the options given below :JEE Mains 2024 Medium
- \(10.0 \,\mathrm{~mL}\) of \(0.05\, \mathrm{M}\, \mathrm{KMnO}_{4}\) solution was consumed in a titration with \(10.0\, \mathrm{~mL}\) of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is \(.....\,\times 10^{-2} \,\mathrm{~g} / \mathrm{L}\) (Round off to the nearest integer)JEE Mains 2021 Medium
- The standard enthalpy of formation \((\Delta _f\,H^o_{298})\) for methane, \(CH_4\) is \(-74.9\,kJ\,mol^{-1}\) . In order to calculate the average energy given out in the formation of a \(C - H\) bond from this it is necessary to know which one of the following?JEE Mains 2014 Hard
- \(37.8 \mathrm{~g} \mathrm{~N}_2 \mathrm{O}_5\) was taken in a 1 L reaction vessel and allowed to undergo the following reaction at 500 K
\(2 \mathrm{~N}_2 \mathrm{O}_{5(\mathrm{~g})} \rightleftharpoons 2 \mathrm{~N}_2 \mathrm{O}_{4(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}\)
The total pressure at equilibrium was found to be 18.65 bar.
Then, \(\mathrm{Kp}=\) ______ \(\times 10^{-2}\) [nearest integer]
Assume \(\mathrm{N}_2 \mathrm{O}_5\) to behave ideally under these conditions.
Given: \(\mathrm{R}=0.082\) bar \(\mathrm{L} \mathrm{mol}^{-1} \mathrm{~K}^{-1}\)JEE Mains 2025 Easy
More PYQs from JEE Mains
- Given below are two statement: one is labelled as Assertion \(A\) and the other is labelled as Reason \(R.\) Assertion \(A:\) \(EM\) waves used for optical communication have longer wavelengths than that of microwave, employed in Radar technology. Reason \(R\) : Infrared \(EM\) waves are more energetic than microwaves, (used in Radar) In the light of given statements, choose the correct answer from the options given below:JEE Mains 2023 Medium
- Identify correct statements :
(A) Primary amines do not give diazonium salts when treated with \(\mathrm{NaNO}_2\) in acidic condition.
(B) Aliphatic and aromatic primary amines on heating with \(\mathrm{CHCl}_3\) and ethanolic KOH form carbylamines.
(C) Secondary and tertiary amines also give carbylamine test.
(D) Benzenesulfonyl chloride is known as Hinsberg's reagent.
(E) Tertiary amines reacts with benzenesulfonyl chloride very easily.
Choose the correct answer from the options given below :JEE Mains 2025 Hard - Which of the following cannot be explained by crystal field theory?JEE Mains 2023 Hard
- Consider the matrices \(A = \begin{bmatrix} 2 & -2 \\ 4 & -2 \end{bmatrix}\) and \(B = \begin{bmatrix} 3 & 9 \\ 1 & 3 \end{bmatrix}\). If matrices P and Q are such that \(PA = B\) and \(AQ = B\), then the absolute value of the sum of the diagonal elements of \(2(P + Q)\) is _______.JEE Mains 2026 Hard
- If \(\left({ }^{30} C_1\right)^2+2\left({ }^{30} C_2\right)^2+3\left({ }^{30} C_3\right)^2 \ldots \ldots \ldots . .30\left({ }^{30} C_{30}\right)^2=\frac{\alpha 60!}{(30!)^2}\), then \(\alpha\) is equal toJEE Mains 2023 Medium
- The number of bent-shaped molecule/s from the following is \(.....\). \(N _3^{-}, NO _2^{-}, I _3^{-}, O _3, SO _2\)JEE Mains 2023 Medium