JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
\(A + 2B \to C\), the rate equation for this reaction is given as Rate \(= K[A][B]\) . If the concentration of \(A\) is kept the same but that of \(B\) is doubled what will happen to the rate it self ?
- A halved
- B the same
- C doubled
- D quadrupled
Answer & Solution
Correct Answer
(C) doubled
Step-by-step Solution
Detailed explanation
Rate \(= K[A][B]=R\) \(R'\, = \,K\left[ A \right]\left[ {2B} \right]\) \(\frac{R}{{R'}}\, = \,\frac{{k[A][B]}}{{k[A][2B]}}\, = \,\frac{{k[A][B]}}{{2k[A][B]}}\) \( \Rightarrow \,2R\, = \,R'\) i.e., rate become doubles.
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