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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

\(A + 2B \to C\), the rate equation for this reaction is given as Rate \(= K[A][B]\) . If the concentration of \(A\) is kept the same but that of \(B\) is doubled what will happen to the rate it self ?

  1. A halved
  2. B the same
  3. C doubled
  4. D quadrupled
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Answer & Solution

Correct Answer

(C) doubled

Step-by-step Solution

Detailed explanation

Rate \(= K[A][B]=R\) \(R'\, = \,K\left[ A \right]\left[ {2B} \right]\) \(\frac{R}{{R'}}\, = \,\frac{{k[A][B]}}{{k[A][2B]}}\, = \,\frac{{k[A][B]}}{{2k[A][B]}}\) \( \Rightarrow \,2R\, = \,R'\) i.e., rate become doubles.
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