JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
Consider the following reactions.
\( PbCl_{2}+K_{2}CrO_{4}\rightarrow A+2KCl \)
(Hot solution)
\( A+NaOH\rightleftharpoons B+Na_{2}CrO_{4} \)
\( PbSO_{4}+4CH_{3}COONH_{4}\rightarrow(NH_{4})_{2}SO_{4}+X \)
In the above reactions, A, B and X are respectively.
- A \( Na_{2}[Pb(OH)_{2}], PbCrO_{4} \) and \( (NH_{4})_{2}[Pb(CH_{3}COO)_{4}] \)
- B \( PbCrO_{4}, Na_{2}[Pb(OH)_{4}] \) and \( [Pb(NH_{3})_{4}]SO_{4} \)
- C \( Na_{2}[Pb(OH)_{2}], PbCrO_{4} \) and \( [Pb(NH_{3})_{4}]SO_{4} \)
- D \( PbCrO_{4}, Na_{2}[Pb(OH)_{4}] \) and \( (NH_{4})_{2}[Pb(CH_{3}COO)_{4}] \)
Answer & Solution
Correct Answer
(D) \( PbCrO_{4}, Na_{2}[Pb(OH)_{4}] \) and \( (NH_{4})_{2}[Pb(CH_{3}COO)_{4}] \)
Step-by-step Solution
Detailed explanation
The reactions are as follows: \( PbCl_{2}+K_{2}CrO_{4}\rightarrow PbCrO_{4}+2KCl \) (Hot solution) \( PbCrO_{4}+4NaOH \) (excess) \( (A) \rightarrow Na_{2}[Pb(OH)_{4}]+Na_{2}CrO_{4} \) \( PbSO_{4}+4CH_{3}COONH_{4} \rightarrow(NH_{4})_{2}[Pb(CH_{3}COO)_{4}]+(NH_{4})_{2}SO_{4} \)
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