JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
A soft drink was bottled with a partial pressure bf \(CO _{2}\) of \(3\) bar over the liquid at room temperature. The partial pressure of \(CO _{2}\) over the solution approaches a value of 30 bar when \(44\, g\) of \(CO _{2}\) is dissolved in \(1\, kg\) of water at room temperature. The approximate \(pH\) of the soft drink is............... \(\times 10^{-1}\) (First dissociation constant of \(H _{2} CO _{3}=4.0 \times 10^{-7}\)\(\log 2=0.3 ;\) density of the soft \(\left.\operatorname{drink}=1\, g\, mL ^{-1}\right)\)
- A \(37\)
- B \(35\)
- C \(40\)
- D \(32\)
Answer & Solution
Correct Answer
(A) \(37\)
Step-by-step Solution
Detailed explanation
\(P _{ CO _{2}}= K _{ H } \times CO _{2}\) \(\frac{3}{30}=\frac{ K _{ H } \cdot n _{ CO _{2}}}{ K _{ H } 1} \Rightarrow n _{ CO _{2}-0.1} mol\) \(pH =\frac{1}{2}\left( pka _{1}-\log c \right)=\frac{1}{2}(6.4 \times 1)=3.7\) \(pH =37 \times 10^{-1}\)
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