JEE Mains · Chemistry · STD 11 - 2. structure of atom
For hydrogen atom, the orbital/s with lowest energy is/are :
(A) 4 s
(B) \(3 \mathrm{p}_x\)
(C) \(3 \mathrm{~d}_{x^2-y^2}\)
(D) \(3 \mathrm{~d}_{z^2}\)
(E) \(4 \mathrm{p}_z\)
Choose the correct answer from the options given below :
- A (B), (C) and (D) only
- B (A) and (E) only
- C (A) only
- D (B) only
Answer & Solution
Correct Answer
(A) (B), (C) and (D) only
Step-by-step Solution
Detailed explanation
For hydrogen atom and one electron species, the energy of orbitals is decided by the value of principal quantum number. Higher the value of principal quantum number, higher will be the energy of orbital. \(\therefore (B),(C)\) and (D) have orbitals with the lowest energy.
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