JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
The following data was obtained for chemical reaction given below at \(975\, \mathrm{~K}\). \(2 \mathrm{NO}_{(\mathrm{g})}+2 \mathrm{H}_{2(\mathrm{~g})} \rightarrow \mathrm{N}_{2(\mathrm{~g})}+2 \mathrm{H}_{2} \mathrm{O}_{(\mathrm{g})}\)
| \([NO]\) \(\mathrm{mol} \mathrm{L}^{-1}\) | \({H}_{2}\) \(\mathrm{mol} \mathrm{L}^{-1}\) | Rate \(\mathrm{mol}L^{-1}\) \(s^{-1}\) | |
| \((A)\) | \(8 \times 10^{-5}\) | \(8 \times 10^{-5}\) | \(7 \times 10^{-9}\) |
| \((B)\) | \(24 \times 10^{-5}\) | \(8 \times 10^{-5}\) | \(2.1 \times 10^{-8}\) |
| \((C)\) | \(24 \times 10^{-5}\) | \(32 \times 10^{-5}\) | \(8.4 \times 10^{-8}\) |
- A \(1\)
- B \(4\)
- C \(2\)
- D \(3\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
\(7 \times 10^{-9}=\mathrm{K} \times\left(8 \times 10^{-5}\right)^{\mathrm{x}}\left(8 \times 10^{-5}\right)^{\mathrm{y}} \ldots \ldots . .(1)\)…
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