ExamBro
ExamBro
JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

The following data was obtained for chemical reaction given below at \(975\, \mathrm{~K}\). \(2 \mathrm{NO}_{(\mathrm{g})}+2 \mathrm{H}_{2(\mathrm{~g})} \rightarrow \mathrm{N}_{2(\mathrm{~g})}+2 \mathrm{H}_{2} \mathrm{O}_{(\mathrm{g})}\)
  \([NO]\) \(\mathrm{mol} \mathrm{L}^{-1}\) \({H}_{2}\) \(\mathrm{mol} \mathrm{L}^{-1}\) Rate  \(\mathrm{mol}L^{-1}\) \(s^{-1}\)
\((A)\) \(8 \times 10^{-5}\) \(8 \times 10^{-5}\) \(7 \times 10^{-9}\)
\((B)\) \(24 \times 10^{-5}\) \(8 \times 10^{-5}\) \(2.1 \times 10^{-8}\)
\((C)\) \(24 \times 10^{-5}\) \(32 \times 10^{-5}\) \(8.4 \times 10^{-8}\)
The order of the reaction with respect to \(\mathrm{NO}\) is ..... .

  1. A \(1\)
  2. B \(4\)
  3. C \(2\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

\(7 \times 10^{-9}=\mathrm{K} \times\left(8 \times 10^{-5}\right)^{\mathrm{x}}\left(8 \times 10^{-5}\right)^{\mathrm{y}} \ldots \ldots . .(1)\)…
From JEE Mains
Explore more questions on app