JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
For a certain thermochemical reaction \(\mathrm{M} \rightarrow \mathrm{N}\) at \(\mathrm{T}=400 \mathrm{~K}, \Delta \mathrm{H}^{\ominus}=77.2 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta \mathrm{S}=122 \mathrm{JK}^{-1}\), \(\log\) equilibrium constant \((\log \mathrm{K})\) is_______ \(\times 10^{-1}\).
- A \(37\)
- B \(38\)
- C \(39\)
- D \(40\)
Answer & Solution
Correct Answer
(A) \(37\)
Step-by-step Solution
Detailed explanation
\( \Delta \mathrm{G}^{\circ}=\Delta \mathrm{H}^{\circ}-\mathrm{T} \Delta \mathrm{S}^{\circ} \) \( =77.2 \times 10^3-400 \times 122=28400 \mathrm{~J} \) \( \Delta \mathrm{G}^{\circ}=-2.303 \mathrm{RT} \log \mathrm{K} \)…
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