JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
An object is dropped from a height \(h\) from the ground. Every time it hits the ground it looses \(50\%\) of its kinetic energy. The total distance covered as \(t \to \infty \) is
- A \(3\,h\)
- B \(\infty \)
- C \(\frac{5}{3}\,h\)
- D \(\frac{8}{3}\,h\)
Answer & Solution
Correct Answer
(A) \(3\,h\)
Step-by-step Solution
Detailed explanation
\(( K.E.)' =50%\) of \(K.E.\) after hit i.e., \(\frac{1}{2}mv{'^2} = \frac{{50}}{{100}} \times \frac{1}{2}m{v^2} \Rightarrow v'\frac{v}{{\sqrt 2 }}\) Coefficient of restitution \( = \frac{1}{{\sqrt 2 }}\) Now, total diatance travelled by object is…
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