JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
Among \(\mathrm{SO}_2, \mathrm{NF}_3, \mathrm{NH}_3, \mathrm{XeF}_2, \mathrm{ClF}_3\) and \(\mathrm{SF}_4\), the hybridization of the molecule with non-zero dipole moment and highest number of lone-pairs of electrons on the central atom is _______.
- A \(\mathrm{sp}^3\)
- B \(\mathrm{dsp}^2\)
- C \(\mathrm{sp}^3 \mathrm{~d}^2\)
- D \(\mathrm{sp}^3 \mathrm{~d}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{sp}^3 \mathrm{~d}\)
Step-by-step Solution
Detailed explanation
\begin{array}{|c|c|c|c|} \hline \text { Molecule } & \text { Hybridisation } & \begin{array}{c} \text { Dipole } \\ \text { Moment } \end{array} & \begin{array}{c} \text { Lone pair on the } \\ \text { central atom } \end{array} \\ \hline \mathrm{SO}_2 & \mathrm{sp}^2 & \text {…
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