JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
During compression of a spring the work done is \(10\,kJ\) and \(2\,kJ\) escaped to the surroundings as heat. The change in internal energy, \(\Delta U\) (in \(kJ\)) is
- A \(8\)
- B \(12\)
- C \(-12\)
- D \(-8\)
Answer & Solution
Correct Answer
(A) \(8\)
Step-by-step Solution
Detailed explanation
Work done on system \(= +10\, kJ\) Heat escaped \(= -2\,kJ\) \(\Delta U = q + w\) \(= 10 -2 = 8\, kJ\)
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