JEE Mains · Physics · STD 12 - 8. Electromagnetic waves

સમતલ ચુંબકીયક્ષેત્ર તરંગમાં ચુંબકીયક્ષેત્ર \(\overrightarrow{ B }( x , t )=\left[1.2 \times 10^{-7} \sin \left(0.5 \times 10^{3} x +1.5 \times 10^{11} t \right) \hat{ k }\right] T\) હોય તો વિદ્યુતક્ષેત્ર શોધો.

A \(\overrightarrow{ E }( x , t )=\left[36 \sin \left(0.5 \times 10^{3} x +1.5 \times 10^{11} t \right) \hat{ k }\right] \frac{ v }{ m }\)
B \(\overrightarrow{ E }( x , t )=\left[-36 \sin \left(0.5 \times 10^{3} x +1.5 \times 10^{11} t \right) \hat{ j }\right] \frac{ v }{ m }\)
C \(\overrightarrow{ E }( x , t )=\left[-36 \sin \left(1 \times 10^{3} x +1.5 \times 10^{11} t \right) \hat{ j }\right] \frac{ v }{ m }\)
D \(\overrightarrow{ E }( x , t )=\left[36 \sin \left(1 \times 10^{3} x +1.5 \times 10^{11} t \right) \hat{ j }\right] \frac{ v }{ m }\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(\overrightarrow{ E }( x , t )=\left[-36 \sin \left(0.5 \times 10^{3} x +1.5 \times 10^{11} t \right) \hat{ j }\right] \frac{ v }{ m }\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow{ E }\) and \(\overrightarrow{ B }\) are perpendicular for \(EM\) wave \(E _{0}= CB _{0}\) \(=3 \times 10^{8} \times 1.2 \times 10^{-7}\) \(=36\) Having same phase Propagation is along \(-x-\)axis, \(\overrightarrow{ B }\) is along \(z-\)axis hence…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From JEE Mains

Explore more questions on app