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JEE Mains · Physics · STD 12 - 8. Electromagnetic waves

સમતલીય વિધુતચુંબકીય તરંગમાં વિધુતક્ષેત્ર \(\overrightarrow{ E }= E _{0}(\hat{ x }+\hat{ y }) \sin ( kz -\omega t )\) મુજબ હોય, તો ચુંબકીયક્ષેત્ર કેટલું હશે?

  1. A \(\frac{ E _{0}}{ c }(\hat{ x }-\hat{ y }) \cos ( kz -\omega t )\)
  2. B \(\frac{ E _{0}}{ c }(-\hat{ x }+\hat{ y }) \sin ( kz -\omega t )\)
  3. C \(\frac{ E _{0}}{ c }(\hat{ x }-\hat{ y }) \sin ( kz -\omega t )\)
  4. D \(\frac{ E _{0}}{ c }(\hat{ x }+\hat{ y }) \sin ( kz -\omega t )\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{ E _{0}}{ c }(-\hat{ x }+\hat{ y }) \sin ( kz -\omega t )\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow{ E }= E _{0}(\hat{ x }+\hat{ y }) \sin ( kz -\omega t )\) direction of propagation \(=+\hat{ k }\) \(\hat{ E }=\frac{\hat{ i }+\hat{ j }}{\sqrt{2}}\) \(\hat{ k }=\hat{ E } \times \hat{ B }\)…
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