પ્રવાહ ધારિત વર્તુળાકાર ગાળાનાં કેન્દ્ર આગળ યુંબકીય ક્ષેત્ર \(B _1\) છે. આપેલ ગાળાના કેન્દ્રથી તેની ત્રિજ્યા કરતા \(\sqrt{3}\) ગણા અંતરે તેની અક્ષ ઉપર ચુંબકીય ક્ષેત્રની \(B _2\) છે. \(B _1\) અને \(B _2\) ગુણોત્તર \(B _1 / B _2................\) થશે.

A \(9: 4\)
B \(12: \sqrt{5}\)
C \(8: 1\)
D \(5: \sqrt{3}\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(8: 1\)

Step-by-step Solution

Detailed explanation

\(B_{1}=\frac{\mu_{0} I}{2 R}\) \(B_{2}=\frac{\mu_{0} I^{2}}{2\left(R^{2}+3 R^{2}\right)^{3 / 2}}=\frac{1}{8}\left(\frac{\mu_{0} I}{2 R}\right)=\frac{B_{1}}{8}\) \(\frac{B_{1}}{B_{2}}=\frac{8}{1}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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