એક નાના ગજિયા ચુંબકને 800 Gauss ના બાહ્યક્ષેત્રમાં તેની અક્ષ \(30^{\circ}\) ખૂણે રહે તેમ મૂકતા તે 0.016 N.m નું ટોર્ક અનુભવે છે.તેને સૌથી સ્થાયી સ્થાનથી સૌથી અસ્થાયી સ્થાનમાં લઈ જવા માટે કરેલું કાર્ય \(\alpha \times 10^{-3} J\) છે. \(\alpha\) નું મૂલ્ય __________ છે.

A 32
B 64
C 16
D 128

Verified Solution

Answer & Solution

Correct Answer

(B) 64

Step-by-step Solution

Detailed explanation

\( \tau=\mu B~sin~\theta\Rightarrow0.016=\mu\times B\times\frac{1}{2} \) \( \Rightarrow\mu=\frac{0.032}{B} \) \( W_{ext}=U_{f}-U_{i}=\mu B-(-\mu B)=2\mu B \) \( =2\times\frac{0.032}{B}\times B \) \( =0.064~J \)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From JEE Mains

Explore more questions on app