ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Physics · STD 12 - 14. Semicondutor electronics

આપેલ પરિપથમાં ઝેનર ડાયોડનો બ્રેકડાઉન, વોલ્ટેજ \(3.0 \mathrm{~V}\) છે. \(I_z\) નું મૂલ્ય કેટલું છે?

  1. A  \(3.3 \mathrm{~mA}\)
  2. B  \(5.5 \mathrm{~mA}\)
  3. C \(10 \mathrm{~mA}\)
  4. D  \(7 \mathrm{~mA}\)
Verified Solution

Answer & Solution

Correct Answer

(B)  \(5.5 \mathrm{~mA}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{V}_z=3 \mathrm{~V}\) Let potential at \(B=0 \mathrm{~V}\) Potential at \(E\left(V_E\right)=10 \mathrm{~V}\) \( V_C=V_A=3 \mathrm{~V} \) \( I_z+I_1=I \) \( I=\frac{10-3}{1000}=\frac{7}{1000} \mathrm{~A} \) \( I_1=\frac{3}{2000} \mathrm{~A}\) Therefore…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app