JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
In the given circuit, the breakdown voltage of the Zener diode is \(3.0 \mathrm{~V}\). What is the value of \(\mathrm{I}_z\) ?
- A \(3.3 \mathrm{~mA}\)
- B \(5.5 \mathrm{~mA}\)
- C \(10 \mathrm{~mA}\)
- D \(7 \mathrm{~mA}\)
Answer & Solution
Correct Answer
(B) \(5.5 \mathrm{~mA}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{V}_z=3 \mathrm{~V}\) Let potential at \(B=0 \mathrm{~V}\) Potential at \(E\left(V_E\right)=10 \mathrm{~V}\) \( V_C=V_A=3 \mathrm{~V} \) \( I_z+I_1=I \) \( I=\frac{10-3}{1000}=\frac{7}{1000} \mathrm{~A} \) \( I_1=\frac{3}{2000} \mathrm{~A}\) Therefore…
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