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JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

\(4\, kg\), નો પદાર્થ  \(10\, ms ^{-1}\) ના વેગથી લંબાઈ  \(8\, m\) અને \(100\, Nm ^{-1}\).બળઅચળાંક ધરાવતી સ્પ્રિંગ સાથે અથડાતાં સ્પ્રિંગની લંબાઈ \(x\, m\) થાય તો \(x\)

  1. A \(4\)
  2. B \(9\)
  3. C \(6\)
  4. D \(12\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(6\)

Step-by-step Solution

Detailed explanation

Let's say the compression in the spring by: \(y\). So, by work energy theorem we have \(\Rightarrow \frac{1}{2} mv ^{2}=\frac{1}{2} ky ^{2}\) \(\Rightarrow y =\sqrt{\frac{ m }{ k }} \cdot v\) \(\Rightarrow y=\sqrt{\frac{4}{100}} \times 10\) \(\Rightarrow y =2\, m\)…
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