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JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

A ball of mass \(4\, kg\), moving with a velocity of \(10\, ms ^{-1}\), collides with a spring of length \(8\, m\) and force constant \(100\, Nm ^{-1}\). The length of the compressed spring is \(x\, m\). The value of \(x\), to the nearest integer, is ........ .

  1. A \(4\)
  2. B \(9\)
  3. C \(6\)
  4. D \(12\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(6\)

Step-by-step Solution

Detailed explanation

Let's say the compression in the spring by: \(y\). So, by work energy theorem we have \(\Rightarrow \frac{1}{2} mv ^{2}=\frac{1}{2} ky ^{2}\) \(\Rightarrow y =\sqrt{\frac{ m }{ k }} \cdot v\) \(\Rightarrow y=\sqrt{\frac{4}{100}} \times 10\) \(\Rightarrow y =2\, m\)…
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