\(10\, {mH}\) ના ઇન્ડક્ટરને \(10\, {k}\, \Omega\) અવરોધ અને સ્વીચ દ્વારા \(20\, {V}\) બેટરી સાથે જોડાયેલ છે. લાંબા સમય પછી, જ્યારે મહત્તમ પ્રવાહ પસાર થાય ત્યારે સ્વીચ બંધ થાય તેવી રીતે પરિપાટ તૈયાર કરેલ છે. \(1\, \mu\, {s}\) પછી પરિપથમાં પ્રવાહ \(\frac{{x}}{100}\, {mA}\) હોય, તો \({x}\) કોને બરાબર થાય? (\({e}^{-1}=0.37\) લો)

A \(71\)
B \(73\)
C \(74\)
D \(80\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(74\)

Step-by-step Solution

Detailed explanation

\(I_{\max }=\frac{V}{R}=\frac{20 V}{10 K \Omega}=2\; mA\) For LR - decay circuit \(I=I_{\max } e ^{- R / L}\; mA\) \(I=2 e ^{\frac{-10 \times 10^{3} \times 1 \times 10^{-6}}{10 \times 10^{-3}}}\; mA\) \(I=2 e ^{-1}\; mA\) \(I=2 \times 0.37\; mA\) \(I=\frac{74}{100}\; mA\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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