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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

ધારોકે \(\alpha, \beta, \gamma\) એ સમીકરણ \(x^3+b x+c=0\) ના ત્રણ બીજ છે. જો \(\beta \gamma=1=-\alpha\) હોય, તો \(b^3+2 c^3-3 \alpha^3-6 \beta^3-8 \gamma^3=..............\)

  1. A \(21\)
  2. B \(\frac{169}{8}\)
  3. C \(19\)
  4. D \(\frac{155}{8}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(19\)

Step-by-step Solution

Detailed explanation

\(\beta \gamma=1\) \(\alpha=-1\) \(\text { Put } \alpha=-1\) \(-1-b+c=0\) \(c-b=1\) \(\text { also }\) \(\alpha \cdot \beta \cdot \gamma=-c\) \(-1=-c \Rightarrow c=1\) \(\therefore b=0\) \(x^3+1=0\) \(\alpha=-1, \beta=- w , \gamma=- w ^2\)…
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