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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

રેખા \(x+\sqrt{3} y=2 \sqrt{3}\) એ નીચેના પૈકી કયા વક્રનો બિંદુ \(\left(\frac{3 \sqrt{3}}{2}, \frac{1}{2}\right)\) આગળનો સ્પર્શક બને ?

  1. A \(x^{2}+y^{2}=7\)
  2. B \(y^{2}=\frac{1}{6 \sqrt{3}} x\)
  3. C \(2 x^{2}-18 y^{2}=9\)
  4. D \(x^{2}+9 y^{2}=9\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(x^{2}+9 y^{2}=9\)

Step-by-step Solution

Detailed explanation

\(m =-\frac{1}{\sqrt{3}}, c =2\) \((1)\) \(c = a \sqrt{1+ m ^{2}}\) \(c =\sqrt{7} \frac{2}{\sqrt{3}}\) (incorrect) \((2)\) \(c =\frac{ a }{ m }=\frac{\frac{1}{24 \sqrt{3}}}{\frac{-1}{\sqrt{3}}}=-\frac{1}{24}\) (incorrect) \((3)\) \(c =\sqrt{ a ^{2} m ^{2}- b ^{2}}\)…
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