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JEE Mains · Maths · STD 11 - 13. statistics

અવલોકનો \(3,5,7,2\,k , 12,16,21,24\) ને ચડતા ક્રમમાં ગોઠવી ને મધ્યસ્થની સરેરાશ વિચલન \(6\)  હોય તો મધ્યસ્થ મેળવો.

  1. A \(11.5\)
  2. B \(10.5\)
  3. C \(12\)
  4. D \(11\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(11\)

Step-by-step Solution

Detailed explanation

Median \(=\frac{2 k+12}{2}=k+6\) Mean deviation \(=\sum \frac{\left|x_{i}-M\right|}{n}=6\) \((k+3)+(k+1)+(k-1)+(6-k)+(6-k)\) \(\frac{+(10-k)+(15-k)+(18-k)}{8}\) \(\therefore \quad \frac{58-2 k}{8}=6\) \(k=5\) Median \(=\frac{2 \times 5+12}{2}=11\)
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