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JEE Mains · Maths · STD 11 - 13. statistics

જો છ અવલોકનો \(7,10,11,15, a, b\) નો મધ્યક અને મધ્યસ્થ અનુક્રમે \(10\) અને \(\frac{20}{3}\), હોય તો  \(|a-b|\) ની કિમંત મેળવો.

  1. A \(7\)
  2. B \(11\)
  3. C \(9\)
  4. D \(1\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1\)

Step-by-step Solution

Detailed explanation

\(10=\frac{7+10+11+15+a+b}{6}\) \(\Rightarrow a+b=17\) \(\frac{20}{3}=\frac{7^{2}+10^{2}+11^{2}+15^{2}+a^{2}+b^{2}}{6}-10^{2}\) \(a^{2}+b^{2}=145\) Solve \((i)\) and \((ii)\) \(\mathrm{a}=9, \mathrm{~b}=8\) or \(\mathrm{a}=8, \mathrm{~b}=9\) \(|a-b|=1\)
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