ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 10. vector algebra

ધારોકે \(\vec{a}\) અને \(\vec{b}\) એવા બે સદિશો છે કે જેથી \(|\vec{a}|=\sqrt{14},|\vec{b}|=\sqrt{6}\) અને \(|\vec{a} \times \vec{b}|=\sqrt{48} \cdot\) તો \((\vec{a} \cdot \vec{b})^2=...........\)

  1. A \(36\)
  2. B \(35\)
  3. C \(37\)
  4. D \(39\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(36\)

Step-by-step Solution

Detailed explanation

\(|\vec{a}|=\sqrt{14},|\vec{b}|=\sqrt{6} \quad|\vec{a} \times \vec{b}|=\sqrt{48}\) \(|\vec{a} \times \vec{b}|^2+|\vec{a} \cdot \vec{b}|^2=|\vec{a}|^2 \times|\vec{b}|^2\) \(\Rightarrow(\vec{a} \cdot \vec{b})^2=84-48=36\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app