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JEE Mains · Maths · STD 12 - 10. vector algebra

माना दो सदिश \(\overrightarrow{\mathrm{a}}\) तथा \(\overrightarrow{\mathrm{b}}\) इस प्रकार है कि \(|\overrightarrow{\mathrm{a}}|=\sqrt{14},|\overrightarrow{\mathrm{b}}|=\sqrt{6}\) तथा \(|\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}|=\sqrt{48}\) है, तो \((\vec{a} \cdot \vec{b})^2\) बराबर है_________. 

  1. A \(36\)
  2. B \(35\)
  3. C \(37\)
  4. D \(39\)
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Answer & Solution

Correct Answer

(A) \(36\)

Step-by-step Solution

Detailed explanation

\(|\vec{a}|=\sqrt{14},|\vec{b}|=\sqrt{6} \quad|\vec{a} \times \vec{b}|=\sqrt{48}\) \(|\vec{a} \times \vec{b}|^2+|\vec{a} \cdot \vec{b}|^2=|\vec{a}|^2 \times|\vec{b}|^2\) \(\Rightarrow(\vec{a} \cdot \vec{b})^2=84-48=36\)
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