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JEE Mains · Maths · STD 12 - 9. differential equations

જો \(y=y(x)\) એ વિકલ સમીકરણ \(16(\sqrt{x+9 \sqrt{x}})(4+\sqrt{9+\sqrt{x}}) \cos y d y=(1+2 \sin y) d x, x>0\) નું સમાધાન કરે અને \(y(256)=\frac{\pi}{2}, y(49)=\alpha\), તો \(2 \sin \alpha =\) ___

  1. A \(2 \sqrt{2}-1\)
  2. B \(2(\sqrt{2}-1)\)
  3. C \(3(\sqrt{2}-1)\)
  4. D \(\sqrt{2}-1\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2 \sqrt{2}-1\)

Step-by-step Solution

Detailed explanation

\(\int \frac{\cos y}{1+2 \sin y} d y=\int \frac{d x}{16(\sqrt{9 \sqrt{x}+x})(4+\sqrt{9+\sqrt{x}})}\) \(4+\sqrt{9+\sqrt{x}}=t\) \(\frac{1}{2 \sqrt{9+\sqrt{x}}} \times \frac{d x}{2 \sqrt{x}}=1 d x\) \(\frac{1}{2} \ell n |1+2 \sin y |=\int \frac{4 dt }{16 t }+ C\)…
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