રેડિયો સમસ્થાનિક બ્રોમિન - \(82\) નો અર્ધ-આયુષ્ય \(36\) hours છે. એક દિવસ પછી બાકી રહતો અંશ (ભાગ) _______ \(\times 10^{-2}\) છે. (આપેલ એન્ટીલોગ (પ્રતિલઘુગુણક) \(0.2006 = 1.587\))

A \(41\)
B \(52\)
C \(63\)
D \(36\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(63\)

Step-by-step Solution

Detailed explanation

બ્રોમિન નો અર્ધ-આયુષ્ય \(-82=36\) hours \( \mathrm{t}_{1 / 2}=\frac{0.693}{\mathrm{~K}} \) \( \mathrm{~K}=\frac{0.693}{36}=0.01925 \mathrm{hr}^{-1} \) \(1^{\text {st }}\) order rxn kinetic equation \( t=\frac{2.303}{K} \log \frac{a}{a-x} \)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

સાચું વિધાન ઓળખો.

JEE Mains 2016 Hard

સૂચિ \(I\) ને સૂચિ \(II\) સાથે જોડો. નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો:

સૂચિ \(-I\)	સૂચિ \(-II\)
\(A.\) ગલનબિંદુ \([\mathrm{K}]\)	\(I.\) \(\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}>\mathrm{Al}>\mathrm{B}\)
\(B.\) આયનીય ત્રિજ્યા \(\left[\mathrm{M}^{+3} / \mathrm{pm}\right]\)	\(II.\) \(\mathrm{B}>\mathrm{Tl}>\mathrm{Al} \approx \mathrm{Ga}>\mathrm{In}\)
\(C.\) \(\Delta_{\mathrm{i}} \mathrm{H}_1 \) \([\mathrm{~kJ} \mathrm{~mol}^{-1}]\)	\(III.\) \(\mathrm{Tl}>\mathrm{In}>\mathrm{Al}>\mathrm{Ga}>\mathrm{B}\)
\(D.\) પરમાણ્વીય ત્રિજ્યા \([pm]\)	\(IV.\) \(\mathrm{B}>\mathrm{Al}>\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}\)

JEE Mains 2024 Medium

Explore more questions on app

From JEE Mains

Explore more questions on app