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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

ઘન \(Ba(NO_3)_2\) \(1.0 \times 10^{-4}\, M\, Na_2CO_3\) દ્રાવણમાં ધીમે ધીમે ઓગળે છે. \(Ba^{2+}\)ની કઈ સાંદ્રતા એ \(BaCO_3\)ના અવક્ષેપ શરૂઆતથી બનશે?(\(BaCO_3 = 5.1 \times 10^{-9}\) માટે \(K_{sp}\))

  1. A \(5.1 \times {10^{ - 5}}\,M\)
  2. B \(7.1 \times {10^{ - 8}}\,M\)
  3. C \(4.1 \times {10^{ - 5}}\,M\)
  4. D \(8.1 \times {10^{ - 7}}\,M\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(5.1 \times {10^{ - 5}}\,M\)

Step-by-step Solution

Detailed explanation

Given \(N{a_2}C{O_3} = 1.0 \times {10^{ - 4}}\,M\) \(\therefore \,[CO_3^ - ] = 1.0 \times {10^{ - 4}}\,M\) \(i.e.\,\,\,s = 1.0 \times {10^{ - 4}}\,M\) At equilibrium \([B{a^{ + + }}][CO_3^ - ] = {K_{sp}}\,of\,BaC{O_3}\)…
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