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JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties

એક દ્રાવકના 50 g માં 1 g અબાષ્પશીલ દ્રાવ્ય (મોલર દળ \(256 \mathrm{~g} \mathrm{~mol}^{-1}\)) હોય અને ઠારબિંદુમાં થતો ઘટાડો 0.40 K હોય, તો તેનો ઠારબિંદુ અવનયન અચળાંક શું છે?

  1. A \(3.72 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
  2. B \(1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
  3. C \(4.43 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
  4. D \(5.12 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(5.12 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} \Delta \mathrm{T}_{\mathrm{f}} & =\mathrm{K}_{\mathrm{b}} \cdot \mathrm{m} \\ 0.4 & =\mathrm{K}_{\mathrm{b}} \frac{\frac{1}{256}}{50 \times 10^{-3}} \\ \mathrm{~K}_{\mathrm{b}} & =5.12 \mathrm{~K} \mathrm{~kg} / \mathrm{mol}\end{aligned}\)
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