બહુઇલેક્ટ્રોન પ્રણાલી માટે ક્વોન્ટમ અંકોના નીચેના ગણોની ઊર્જાઓની તુલના કરો. \((A)\) \(n=4,1=1\) \((B)\) \(\mathrm{n}=4,1=2\) \((C)\) \(\mathrm{n}=3,1=1\) \((D)\) \(\mathrm{n}=3,1=2\) \((E)\) \(n=4,1=0\) નીચે આપેલા વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો:

A \((\mathrm{B})>(\mathrm{A})>(\mathrm{C})>\text { (E) }>\text { (D) }\)
B \((\mathrm{E})>(\mathrm{C})<\text { (D) }<\text { (A) }<\text { (B) }\)
C \({ (E) }>\text { (C) }>\text { (A) }>\text { (D) }>\text { (B) }\)
D \((\mathrm{C})<\text { (E) }<\text { (D) }<\text { (A) }<\text { (B) }\)

Verified Solution

Answer & Solution

Correct Answer

(D) \((\mathrm{C})<\text { (E) }<\text { (D) }<\text { (A) }<\text { (B) }\)

Step-by-step Solution

Detailed explanation

ઊર્જા સ્તર (\(\mathrm{n}+\ell\)) મૂલ્યોની તુલના કરીને નક્કી કરી શકાય છે. \((A)\) \(\mathrm{n}=4, \ell=1 \Rightarrow(\mathrm{n}+\ell)=5\) \((B)\) \(\mathrm{n}=4, \ell=2 \Rightarrow(\mathrm{n}+\ell)=6\) \((C)\) \(\mathrm{n}=3, \ell=1 \Rightarrow(\mathrm{n}+\ell)=4\) \((D\))…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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