JEE Mains · Chemistry · STD 11 - 2. structure of atom
Compare the energies of following sets of quantum numbers for multielectron system. \((A)\) \(n=4,1=1\) \((B)\) \(\mathrm{n}=4,1=2\) \((C)\) \(\mathrm{n}=3,1=1\) \((D)\) \(\mathrm{n}=3,1=2\) \((E)\) \(n=4,1=0\) Choose the correct answer from the options given below:
- A \((\mathrm{B})>(\mathrm{A})>(\mathrm{C})>\text { (E) }>\text { (D) }\)
- B \((\mathrm{E})>(\mathrm{C})<\text { (D) }<\text { (A) }<\text { (B) }\)
- C \({ (E) }>\text { (C) }>\text { (A) }>\text { (D) }>\text { (B) }\)
- D \((\mathrm{C})<\text { (E) }<\text { (D) }<\text { (A) }<\text { (B) }\)
Answer & Solution
Correct Answer
(D) \((\mathrm{C})<\text { (E) }<\text { (D) }<\text { (A) }<\text { (B) }\)
Step-by-step Solution
Detailed explanation
Energy level can be determined by comparing ( \(\mathrm{n}+\ell\) ) values \((A)\) \(\mathrm{n}=4, \ell=1 \Rightarrow(\mathrm{n}+\ell)=5\) \((B)\) \(\mathrm{n}=4, \ell=2 \Rightarrow(\mathrm{n}+\ell)=6\) \((C)\) \(\mathrm{n}=3, \ell=1 \Rightarrow(\mathrm{n}+\ell)=4\) \((D\))…
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