બાષ્પદબાણમાં \(75\%\) નો ઘટાડો કરવા \(114\,g\) ઓક્ટેનમાં દ્રાવ્ય કરવા પડતા અબાષ્પશીલ, વિધુતઅવિભાજ્ય દ્રાવ્ય (મોલર દળ \(= 50\,g\,mol^{- 1})\) નુ દળ ........... \(\mathrm{g}\) જણાવો.

A \(37.5\)
B \(75\)
C \(150\)
D \(50\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(150\)

Step-by-step Solution

Detailed explanation

Molar mass of octane \(=\,114\,g/mol\) From the lowering of vapour pressure we have, \(\frac{{\Delta P}}{P} = \frac{{\frac{{{W_2}}}{{{M_2}}}}}{{\frac{{{W_2}}}{{{M_2}}} + \frac{{{W_1}}}{{{M_1}}}}}\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

યાદી - I ને યાદી - II સાથે જોડો.

સૂચિ - I (આંશિક વ્યુત્પન્ન)	સૂચિ - II (થર્મોડાયનેમિક જથ્થો)
(A)\(\left(\frac{\partial \mathrm{G}}{\partial \mathrm{T}}\right)_{\mathrm{P}}\)	(I) Cp
(B) \(\left(\frac{\partial \mathrm{H}}{\partial \mathrm{T}}\right)_{\mathrm{P}}\)	(II) -S
(C) \(\left(\frac{\partial G}{\partial P}\right)_T\)	(III) Cv
(D) \(\left(\frac{\partial \mathrm{U}}{\partial \mathrm{T}}\right)_{\mathrm{V}}\)	(IV) V

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JEE Mains 2025 Hard

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